Passing Parameter Using Html Form in Servlet

March 02, 2014 by Mukesh Kumar at 3:47 pm

The parameters are the way in which a user can send information to the Http Server. For example, in a login screen, we need to send to the server, the user and the password so that it validates them.

To implement this requirement we have to make one html form which will have two fields named as username and password in which user will enter username and password. And we will also have one submit button, on pressing the submit button the request will go to the server and servlet will do the corresponding validation.

In the servlet class will collect the values from login form page by using the method getParameter().The output will be displayed to you by the object of the PrintWriter class.

The parameters are the way in which a user can send information to the Http Server. For example, in a login screen, we need to send to the server, the user and the password so that it validates them.

In the servlet class will collect the values from login form page by using the method getParameter().The output will be displayed to you by the object of the PrintWriter class.

Directory Structure Of Project

Servlet Passing Parameter

The code of the program is given below:

login.jsp

<html>

<head>
<title>Login Form</title>
</head>
<body>
	<h2>Login Page</h2>
	<p>Please enter your username and password</p>
	<form method="GET" action="loginServlet">
		<p>
			Username <input type="text" name="userName" size="50">
		</p>
		<p>
			Password <input type="text" name="password" size="20">
		</p>
		<p>
			<input type="submit" value="Submit" name="B1">
		</p>
	</form>
	<p>&nbsp;</p>
</body>
</html>

LoginServlet.java

package com.jwt.servlet;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class LoginServlet extends HttpServlet {
	public void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		response.setContentType("text/html");
		PrintWriter out = response.getWriter();
		String userName = request.getParameter("userName");
		String password = request.getParameter("password");
		out.println("<html>");
		out.println("<body>");
		out.println("Hello " + "  " + userName + "welcome to my blog");
		out.println("Your password is : " + "  " + password + "<br>");
		out.println("</body></html>");
	}
}

web.xml

Map the servlet in web.xml file

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
	id="WebApp_ID" version="2.5">
	<display-name>FormExample</display-name>
	<servlet>
		<servlet-name>LoginServlet</servlet-name>
		<servlet-class>com.jwt.servlet.LoginServlet</servlet-class>
	</servlet>
	<servlet-mapping>
		<servlet-name>LoginServlet</servlet-name>
		<url-pattern>/loginServlet</url-pattern>
	</servlet-mapping>
	<welcome-file-list>
		<welcome-file>login.jsp</welcome-file>
	</welcome-file-list>
</web-app>